In the figure given below, O is the center of line joining AB. Two charges of opposite nature and same magnitude are placed at points A and B, respectively.
The potential at point P is
A
B
zero
C
D
cannot be determined
Text Solution
Verified by ExpertsThe correct answer is:
B
As O is the center of line AB, so 
and the distance of point P from A and B is
The potential at P due to charge +q at A and -q at B is
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